Base | Representation |
---|---|
bin | 11001101101111111110001… |
… | …010100000111011100010111 |
3 | 112211111101212121202121120022 |
4 | 121231333301110013130113 |
5 | 104311211400123310313 |
6 | 1040322535140055355 |
7 | 32553034053021041 |
oct | 3155776124073427 |
9 | 484441777677508 |
10 | 113112012322583 |
11 | 3304a59814a79a |
12 | 10829a4809455b |
13 | 4b1655619b381 |
14 | 1dd09173a2a91 |
15 | d12482a47c08 |
hex | 66dff1507717 |
113112012322583 has 2 divisors, whose sum is σ = 113112012322584. Its totient is φ = 113112012322582.
The previous prime is 113112012322559. The next prime is 113112012322601. The reversal of 113112012322583 is 385223210211311.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 113112012322583 - 214 = 113112012306199 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (113112012322553) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 56556006161291 + 56556006161292.
It is an arithmetic number, because the mean of its divisors is an integer number (56556006161292).
Almost surely, 2113112012322583 is an apocalyptic number.
113112012322583 is a deficient number, since it is larger than the sum of its proper divisors (1).
113112012322583 is an equidigital number, since it uses as much as digits as its factorization.
113112012322583 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 17280, while the sum is 35.
Adding to 113112012322583 its reverse (385223210211311), we get a palindrome (498335222533894).
The spelling of 113112012322583 in words is "one hundred thirteen trillion, one hundred twelve billion, twelve million, three hundred twenty-two thousand, five hundred eighty-three".
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