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11311214612500 = 22551128219109
BaseRepresentation
bin1010010010011001100011…
…1011011101000000010100
31111001100012222212001022001
42210212120323131000110
52440310331420100000
640020144504445044
72245131304556155
oct244463073350024
944040188761261
1011311214612500
113671071847600
121328232a79784
1364084877c73a
142b1673c9192c
1514936d69b46a
hexa4998edd014

11311214612500 has 216 divisors, whose sum is σ = 27231534492120. Its totient is φ = 4107708000000.

The previous prime is 11311214612483. The next prime is 11311214612507. The reversal of 11311214612500 is 521641211311.

It is a happy number.

It can be written as a sum of positive squares in 12 ways, for example, as 10315106817796 + 996107794704 = 3211714^2 + 998052^2 .

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (11311214612507) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 71 ways as a sum of consecutive naturals, for example, 1241757946 + ... + 1241767054.

It is an arithmetic number, because the mean of its divisors is an integer number (126071918945).

Almost surely, 211311214612500 is an apocalyptic number.

11311214612500 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

It is a practical number, because each smaller number is the sum of distinct divisors of 11311214612500, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (13615767246060).

11311214612500 is an abundant number, since it is smaller than the sum of its proper divisors (15920319879620).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

11311214612500 is an equidigital number, since it uses as much as digits as its factorization.

11311214612500 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 9981 (or 9948 counting only the distinct ones).

The product of its (nonzero) digits is 1440, while the sum is 28.

Adding to 11311214612500 its reverse (521641211311), we get a palindrome (11832855823811).

The spelling of 11311214612500 in words is "eleven trillion, three hundred eleven billion, two hundred fourteen million, six hundred twelve thousand, five hundred".