Base | Representation |
---|---|
bin | 10000011101011100001… |
… | …100010100001101011111 |
3 | 11000010121220201122111212 |
4 | 100131130030110031133 |
5 | 122013020010144411 |
6 | 2223344130135035 |
7 | 144502166656322 |
oct | 20353414241537 |
9 | 4003556648455 |
10 | 1131123131231 |
11 | 3a6785579155 |
12 | 163276a2147b |
13 | 82883a5c762 |
14 | 3ca64b527b9 |
15 | 1e652ece68b |
hex | 1075c31435f |
1131123131231 has 2 divisors, whose sum is σ = 1131123131232. Its totient is φ = 1131123131230.
The previous prime is 1131123131191. The next prime is 1131123131249. The reversal of 1131123131231 is 1321313211311.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 1131123131231 - 218 = 1131122869087 is a prime.
It is a super-2 number, since 2×11311231312312 (a number of 25 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 1131123131197 and 1131123131206.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (1131123131291) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 565561565615 + 565561565616.
It is an arithmetic number, because the mean of its divisors is an integer number (565561565616).
Almost surely, 21131123131231 is an apocalyptic number.
1131123131231 is a deficient number, since it is larger than the sum of its proper divisors (1).
1131123131231 is an equidigital number, since it uses as much as digits as its factorization.
1131123131231 is an evil number, because the sum of its binary digits is even.
The product of its digits is 324, while the sum is 23.
Adding to 1131123131231 its reverse (1321313211311), we get a palindrome (2452436342542).
The spelling of 1131123131231 in words is "one trillion, one hundred thirty-one billion, one hundred twenty-three million, one hundred thirty-one thousand, two hundred thirty-one".
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