Base | Representation |
---|---|
bin | 1010010010011001101011… |
… | …0001010111001000011000 |
3 | 1111001100022011000101101022 |
4 | 2210212122301113020120 |
5 | 2440310412323141212 |
6 | 40020151531142012 |
7 | 2245132131361523 |
oct | 244463261271030 |
9 | 44040264011338 |
10 | 11311245521432 |
11 | 367108823897a |
12 | 13282412a4908 |
13 | 640851cb234c |
14 | 2b1678019bba |
15 | 149371254772 |
hex | a499ac57218 |
11311245521432 has 16 divisors (see below), whose sum is σ = 21209218551000. Its totient is φ = 5655453907840.
The previous prime is 11311245521431. The next prime is 11311245521449. The reversal of 11311245521432 is 23412554211311.
It is a super-2 number, since 2×113112455214322 (a number of 27 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 11311245521392 and 11311245521401.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (11311245521431) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 20821682 + ... + 21358017.
Almost surely, 211311245521432 is an apocalyptic number.
It is an amenable number.
11311245521432 is a deficient number, since it is larger than the sum of its proper divisors (9897973029568).
11311245521432 is a wasteful number, since it uses less digits than its factorization.
11311245521432 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 42213226 (or 42213222 counting only the distinct ones).
The product of its digits is 28800, while the sum is 35.
Adding to 11311245521432 its reverse (23412554211311), we get a palindrome (34723799732743).
The spelling of 11311245521432 in words is "eleven trillion, three hundred eleven billion, two hundred forty-five million, five hundred twenty-one thousand, four hundred thirty-two".
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