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11311245521431 is a prime number
BaseRepresentation
bin1010010010011001101011…
…0001010111001000010111
31111001100022011000101101021
42210212122301113020113
52440310412323141211
640020151531142011
72245132131361522
oct244463261271027
944040264011337
1011311245521431
113671088238979
1213282412a4907
13640851cb234b
142b1678019bb9
15149371254771
hexa499ac57217

11311245521431 has 2 divisors, whose sum is σ = 11311245521432. Its totient is φ = 11311245521430.

The previous prime is 11311245521423. The next prime is 11311245521449. The reversal of 11311245521431 is 13412554211311.

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 11311245521431 - 23 = 11311245521423 is a prime.

It is a super-2 number, since 2×113112455214312 (a number of 27 digits) contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (11311245521491) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5655622760715 + 5655622760716.

It is an arithmetic number, because the mean of its divisors is an integer number (5655622760716).

Almost surely, 211311245521431 is an apocalyptic number.

11311245521431 is a deficient number, since it is larger than the sum of its proper divisors (1).

11311245521431 is an equidigital number, since it uses as much as digits as its factorization.

11311245521431 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 14400, while the sum is 34.

Adding to 11311245521431 its reverse (13412554211311), we get a palindrome (24723799732742).

The spelling of 11311245521431 in words is "eleven trillion, three hundred eleven billion, two hundred forty-five million, five hundred twenty-one thousand, four hundred thirty-one".