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113113012147 is a prime number
BaseRepresentation
bin110100101011000001…
…1111001011110110011
3101210222001002101020021
41221112003321132303
53323123412342042
6123544032224311
711113021511422
oct1512603713663
9353861071207
10113113012147
1143a7538a223
1219b0939b097
13a88842c825
1456908072b9
152e20561867
hex1a560f97b3

113113012147 has 2 divisors, whose sum is σ = 113113012148. Its totient is φ = 113113012146.

The previous prime is 113113012121. The next prime is 113113012163. The reversal of 113113012147 is 741210311311.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 113113012147 - 215 = 113112979379 is a prime.

It is not a weakly prime, because it can be changed into another prime (113113012447) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 56556506073 + 56556506074.

It is an arithmetic number, because the mean of its divisors is an integer number (56556506074).

Almost surely, 2113113012147 is an apocalyptic number.

113113012147 is a deficient number, since it is larger than the sum of its proper divisors (1).

113113012147 is an equidigital number, since it uses as much as digits as its factorization.

113113012147 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 504, while the sum is 25.

Adding to 113113012147 its reverse (741210311311), we get a palindrome (854323323458).

The spelling of 113113012147 in words is "one hundred thirteen billion, one hundred thirteen million, twelve thousand, one hundred forty-seven".