1131131200130 has 32 divisors (see below), whose sum is σ = 2101803199488. Its totient is φ = 437838811200.

The previous prime is 1131131200127. The next prime is 1131131200151. The reversal of 1131131200130 is 310021311311.

It is a super-2 number, since 2×1131131200130² (a number of 25 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 1131131200099 and 1131131200108.

It is an unprimeable number.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 9046640 + ... + 9170820.

It is an arithmetic number, because the mean of its divisors is an integer number (65681349984).

Almost surely, 2^{1131131200130} is an apocalyptic number.

1131131200130 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

1131131200130 is a deficient number, since it is larger than the sum of its proper divisors (970671999358).

1131131200130 is a wasteful number, since it uses less digits than its factorization.

1131131200130 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 153602.

The product of its (nonzero) digits is 54, while the sum is 17.

Adding to 1131131200130 its reverse (310021311311), we get a palindrome (1441152511441).

The spelling of 1131131200130 in words is "one trillion, one hundred thirty-one billion, one hundred thirty-one million, two hundred thousand, one hundred thirty".