Base | Representation |
---|---|
bin | 10000011101011100101… |
… | …011100001011111101111 |
3 | 11000010122111010021120102 |
4 | 100131130223201133233 |
5 | 122013024103441421 |
6 | 2223345021341315 |
7 | 144502326341303 |
oct | 20353453413757 |
9 | 4003574107512 |
10 | 1131131312111 |
11 | 3a678a156609 |
12 | 16327970783b |
13 | 82885665308 |
14 | 3ca65c81d03 |
15 | 1e653a9860b |
hex | 1075cae17ef |
1131131312111 has 2 divisors, whose sum is σ = 1131131312112. Its totient is φ = 1131131312110.
The previous prime is 1131131312089. The next prime is 1131131312147. The reversal of 1131131312111 is 1112131311311.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 1131131312111 - 210 = 1131131311087 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (1131131612111) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 565565656055 + 565565656056.
It is an arithmetic number, because the mean of its divisors is an integer number (565565656056).
Almost surely, 21131131312111 is an apocalyptic number.
1131131312111 is a deficient number, since it is larger than the sum of its proper divisors (1).
1131131312111 is an equidigital number, since it uses as much as digits as its factorization.
1131131312111 is an evil number, because the sum of its binary digits is even.
The product of its digits is 54, while the sum is 20.
Adding to 1131131312111 its reverse (1112131311311), we get a palindrome (2243262623422).
The spelling of 1131131312111 in words is "one trillion, one hundred thirty-one billion, one hundred thirty-one million, three hundred twelve thousand, one hundred eleven".
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