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11311340440123 is a prime number
BaseRepresentation
bin1010010010011010000001…
…1011011100101000111011
31111001100112202121202100101
42210212200123130220323
52440311111123040443
640020205201420231
72245134363231433
oct244464033345073
944040482552311
1011311340440123
113671126879779
12132826903a677
13640868867059
142b16868872c3
1514937975384d
hexa49a06dca3b

11311340440123 has 2 divisors, whose sum is σ = 11311340440124. Its totient is φ = 11311340440122.

The previous prime is 11311340440121. The next prime is 11311340440133. The reversal of 11311340440123 is 32104404311311.

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 11311340440123 - 21 = 11311340440121 is a prime.

Together with 11311340440121, it forms a pair of twin primes.

It is a junction number, because it is equal to n+sod(n) for n = 11311340440091 and 11311340440100.

It is not a weakly prime, because it can be changed into another prime (11311340440121) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5655670220061 + 5655670220062.

It is an arithmetic number, because the mean of its divisors is an integer number (5655670220062).

Almost surely, 211311340440123 is an apocalyptic number.

11311340440123 is a deficient number, since it is larger than the sum of its proper divisors (1).

11311340440123 is an equidigital number, since it uses as much as digits as its factorization.

11311340440123 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 3456, while the sum is 28.

Adding to 11311340440123 its reverse (32104404311311), we get a palindrome (43415744751434).

The spelling of 11311340440123 in words is "eleven trillion, three hundred eleven billion, three hundred forty million, four hundred forty thousand, one hundred twenty-three".