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11311400213042 = 219297668426659
BaseRepresentation
bin1010010010011010001111…
…1111011101101000110010
31111001100200221002112101012
42210212203333131220302
52440311221423304132
640020215134510522
72245136020261466
oct244464377355062
944040627075335
1011311400213042
113671157594a86
121328285065442
13640878064847
142b16907a64a6
1514937eb0e0b2
hexa49a3fdda32

11311400213042 has 8 divisors (see below), whose sum is σ = 17860105599600. Its totient is φ = 5358031679844.

The previous prime is 11311400213041. The next prime is 11311400213093. The reversal of 11311400213042 is 24031200411311.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a junction number, because it is equal to n+sod(n) for n = 11311400212999 and 11311400213017.

It is not an unprimeable number, because it can be changed into a prime (11311400213041) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 148834213292 + ... + 148834213367.

It is an arithmetic number, because the mean of its divisors is an integer number (2232513199950).

Almost surely, 211311400213042 is an apocalyptic number.

11311400213042 is a deficient number, since it is larger than the sum of its proper divisors (6548705386558).

11311400213042 is a wasteful number, since it uses less digits than its factorization.

11311400213042 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 297668426680.

The product of its (nonzero) digits is 576, while the sum is 23.

Adding to 11311400213042 its reverse (24031200411311), we get a palindrome (35342600624353).

The spelling of 11311400213042 in words is "eleven trillion, three hundred eleven billion, four hundred million, two hundred thirteen thousand, forty-two".

Divisors: 1 2 19 38 297668426659 595336853318 5655700106521 11311400213042