Base | Representation |
---|---|
bin | 1010010010011010001111… |
… | …1111011101101001100101 |
3 | 1111001100200221002112110002 |
4 | 2210212203333131221211 |
5 | 2440311221423304333 |
6 | 40020215134511045 |
7 | 2245136020261601 |
oct | 244464377355145 |
9 | 44040627075402 |
10 | 11311400213093 |
11 | 3671157595022 |
12 | 1328285065485 |
13 | 640878064886 |
14 | 2b16907a6501 |
15 | 14937eb0e0e8 |
hex | a49a3fdda65 |
11311400213093 has 2 divisors, whose sum is σ = 11311400213094. Its totient is φ = 11311400213092.
The previous prime is 11311400213041. The next prime is 11311400213111. The reversal of 11311400213093 is 39031200411311.
It is a happy number.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 9297334017409 + 2014066195684 = 3049153^2 + 1419178^2 .
It is a cyclic number.
It is not a de Polignac number, because 11311400213093 - 226 = 11311333104229 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (11311400243093) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5655700106546 + 5655700106547.
It is an arithmetic number, because the mean of its divisors is an integer number (5655700106547).
Almost surely, 211311400213093 is an apocalyptic number.
It is an amenable number.
11311400213093 is a deficient number, since it is larger than the sum of its proper divisors (1).
11311400213093 is an equidigital number, since it uses as much as digits as its factorization.
11311400213093 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 1944, while the sum is 29.
The spelling of 11311400213093 in words is "eleven trillion, three hundred eleven billion, four hundred million, two hundred thirteen thousand, ninety-three".
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