11311433133 has 192 divisors, whose sum is σ = 21533589504. Its totient is φ = 5121792000.

The previous prime is 11311433131. The next prime is 11311433137. The reversal of 11311433133 is 33133411311.

11311433133 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is not a de Polignac number, because 11311433133 - 2¹ = 11311433131 is a prime.

It is a super-4 number, since 4×11311433133⁴ (a number of 41 digits) contains 4444 as substring.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (11311433131) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 191 ways as a sum of consecutive naturals, for example, 59222068 + ... + 59222258.

It is an arithmetic number, because the mean of its divisors is an integer number (112154112).

Almost surely, 2^11311433133 is an apocalyptic number.

11311433133 is a gapful number since it is divisible by the number (13) formed by its first and last digit.

It is an amenable number.

11311433133 is a deficient number, since it is larger than the sum of its proper divisors (10222156371).

11311433133 is a wasteful number, since it uses less digits than its factorization.

11311433133 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 316 (or 303 counting only the distinct ones).

The product of its digits is 972, while the sum is 24.

Adding to 11311433133 its reverse (33133411311), we get a palindrome (44444844444).

It can be divided in two parts, 11311 and 433133, that added together give a palindrome (444444).

The spelling of 11311433133 in words is "eleven billion, three hundred eleven million, four hundred thirty-three thousand, one hundred thirty-three".