Base | Representation |
---|---|
bin | 1010010010011010011001… |
… | …1111010101100101001011 |
3 | 1111001100210211221210010221 |
4 | 2210212212133111211023 |
5 | 2440311313140414313 |
6 | 40020223233050511 |
7 | 2245140036433264 |
oct | 244464637254513 |
9 | 44040724853127 |
10 | 11311442123083 |
11 | 367117920a683 |
12 | 13282970b6a37 |
13 | 64088394989b |
14 | 2b169619596b |
15 | 14938363bc8d |
hex | a49a67d594b |
11311442123083 has 2 divisors, whose sum is σ = 11311442123084. Its totient is φ = 11311442123082.
The previous prime is 11311442123039. The next prime is 11311442123227. The reversal of 11311442123083 is 38032124411311.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 11311442123083 - 29 = 11311442122571 is a prime.
It is not a weakly prime, because it can be changed into another prime (11311442129083) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5655721061541 + 5655721061542.
It is an arithmetic number, because the mean of its divisors is an integer number (5655721061542).
Almost surely, 211311442123083 is an apocalyptic number.
11311442123083 is a deficient number, since it is larger than the sum of its proper divisors (1).
11311442123083 is an equidigital number, since it uses as much as digits as its factorization.
11311442123083 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 13824, while the sum is 34.
Adding to 11311442123083 its reverse (38032124411311), we get a palindrome (49343566534394).
The spelling of 11311442123083 in words is "eleven trillion, three hundred eleven billion, four hundred forty-two million, one hundred twenty-three thousand, eighty-three".
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