Base | Representation |
---|---|
bin | 110100101011000100… |
… | …1010111001010010101 |
3 | 101210222010210010222001 |
4 | 1221112021113022111 |
5 | 3323124244210222 |
6 | 123544123035301 |
7 | 11113036625251 |
oct | 1512611271225 |
9 | 353863703861 |
10 | 113114444437 |
11 | 43a76178335 |
12 | 19b0996bb31 |
13 | a888811737 |
14 | 5690a9b261 |
15 | 2e20745e27 |
hex | 1a56257295 |
113114444437 has 2 divisors, whose sum is σ = 113114444438. Its totient is φ = 113114444436.
The previous prime is 113114444389. The next prime is 113114444441. The reversal of 113114444437 is 734444411311.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 102767689476 + 10346754961 = 320574^2 + 101719^2 .
It is a cyclic number.
It is not a de Polignac number, because 113114444437 - 27 = 113114444309 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 113114444396 and 113114444405.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (113114444477) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 56557222218 + 56557222219.
It is an arithmetic number, because the mean of its divisors is an integer number (56557222219).
Almost surely, 2113114444437 is an apocalyptic number.
It is an amenable number.
113114444437 is a deficient number, since it is larger than the sum of its proper divisors (1).
113114444437 is an equidigital number, since it uses as much as digits as its factorization.
113114444437 is an evil number, because the sum of its binary digits is even.
The product of its digits is 64512, while the sum is 37.
Adding to 113114444437 its reverse (734444411311), we get a palindrome (847558855748).
The spelling of 113114444437 in words is "one hundred thirteen billion, one hundred fourteen million, four hundred forty-four thousand, four hundred thirty-seven".
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