Base | Representation |
---|---|
bin | 1010010010011010101011… |
… | …1001100011111001011111 |
3 | 1111001101000000011112002101 |
4 | 2210212222321203321133 |
5 | 2440311441110400320 |
6 | 40020234434505531 |
7 | 2245141625330014 |
oct | 244465271437137 |
9 | 44041000145071 |
10 | 11311516106335 |
11 | 3671206a51365 |
12 | 13282b7a352a7 |
13 | 640896081463 |
14 | 2b16a1d3370b |
15 | 149389da2c0a |
hex | a49aae63e5f |
11311516106335 has 32 divisors (see below), whose sum is σ = 14560980318720. Its totient is φ = 8409359088000.
The previous prime is 11311516106327. The next prime is 11311516106339. The reversal of 11311516106335 is 53360161511311.
It is not a de Polignac number, because 11311516106335 - 23 = 11311516106327 is a prime.
It is a super-2 number, since 2×113115161063352 (a number of 27 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 11311516106294 and 11311516106303.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (11311516106339) by changing a digit.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 23176270 + ... + 23659300.
It is an arithmetic number, because the mean of its divisors is an integer number (455030634960).
Almost surely, 211311516106335 is an apocalyptic number.
11311516106335 is a deficient number, since it is larger than the sum of its proper divisors (3249464212385).
11311516106335 is a wasteful number, since it uses less digits than its factorization.
11311516106335 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 487759.
The product of its (nonzero) digits is 24300, while the sum is 37.
Adding to 11311516106335 its reverse (53360161511311), we get a palindrome (64671677617646).
The spelling of 11311516106335 in words is "eleven trillion, three hundred eleven billion, five hundred sixteen million, one hundred six thousand, three hundred thirty-five".
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