Base | Representation |
---|---|
bin | 10000011101011110000… |
… | …000010101000010101101 |
3 | 11000010201000221202002022 |
4 | 100131132000111002231 |
5 | 122013100301341331 |
6 | 2223351134035525 |
7 | 144503016322343 |
oct | 20353600250255 |
9 | 4003630852068 |
10 | 1131153543341 |
11 | 3a67a0760228 |
12 | 163285048ba5 |
13 | 8288a14a1a3 |
14 | 3ca68bcb993 |
15 | 1e6559da67b |
hex | 1075e0150ad |
1131153543341 has 2 divisors, whose sum is σ = 1131153543342. Its totient is φ = 1131153543340.
The previous prime is 1131153543283. The next prime is 1131153543391. The reversal of 1131153543341 is 1433453511311.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 1125623390116 + 5530153225 = 1060954^2 + 74365^2 .
It is a cyclic number.
It is not a de Polignac number, because 1131153543341 - 26 = 1131153543277 is a prime.
It is a super-2 number, since 2×11311535433412 (a number of 25 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (1131153543391) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 565576771670 + 565576771671.
It is an arithmetic number, because the mean of its divisors is an integer number (565576771671).
Almost surely, 21131153543341 is an apocalyptic number.
It is an amenable number.
1131153543341 is a deficient number, since it is larger than the sum of its proper divisors (1).
1131153543341 is an equidigital number, since it uses as much as digits as its factorization.
1131153543341 is an odious number, because the sum of its binary digits is odd.
The product of its digits is 32400, while the sum is 35.
The spelling of 1131153543341 in words is "one trillion, one hundred thirty-one billion, one hundred fifty-three million, five hundred forty-three thousand, three hundred forty-one".
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