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113119999997 is a prime number
BaseRepresentation
bin110100101011001111…
…0100011011111111101
3101210222112020101202112
41221112132203133331
53323132204444442
6123544442103405
711113135064234
oct1512636433775
9353875211675
10113119999997
1143a79322304
1219b0b7aab65
13a889a08354
145691705b1b
152e20e92082
hex1a567a37fd

113119999997 has 2 divisors, whose sum is σ = 113119999998. Its totient is φ = 113119999996.

The previous prime is 113119999961. The next prime is 113120000057. The reversal of 113119999997 is 799999911311.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 104325124036 + 8794875961 = 322994^2 + 93781^2 .

It is an emirp because it is prime and its reverse (799999911311) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 113119999997 - 210 = 113119998973 is a prime.

It is a super-2 number, since 2×1131199999972 (a number of 23 digits) contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (113119998997) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 56559999998 + 56559999999.

It is an arithmetic number, because the mean of its divisors is an integer number (56559999999).

Almost surely, 2113119999997 is an apocalyptic number.

It is an amenable number.

113119999997 is a deficient number, since it is larger than the sum of its proper divisors (1).

113119999997 is an equidigital number, since it uses as much as digits as its factorization.

113119999997 is an evil number, because the sum of its binary digits is even.

The product of its digits is 11160261, while the sum is 68.

The spelling of 113119999997 in words is "one hundred thirteen billion, one hundred nineteen million, nine hundred ninety-nine thousand, nine hundred ninety-seven".