Base | Representation |
---|---|
bin | 1010010010011100100001… |
… | …1001100011100111000011 |
3 | 1111001102021111110101212121 |
4 | 2210213020121203213003 |
5 | 2440313444311024102 |
6 | 40020355514505111 |
7 | 2245160115203665 |
oct | 244471031434703 |
9 | 44042244411777 |
10 | 11312011033027 |
11 | 3671440363091 |
12 | 1328415735197 |
13 | 64094477b2a3 |
14 | 2b170b968535 |
15 | 1493b8567b37 |
hex | a49c86639c3 |
11312011033027 has 2 divisors, whose sum is σ = 11312011033028. Its totient is φ = 11312011033026.
The previous prime is 11312011032953. The next prime is 11312011033033. The reversal of 11312011033027 is 72033011021311.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 11312011033027 - 231 = 11309863549379 is a prime.
It is a super-2 number, since 2×113120110330272 (a number of 27 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 11312011032992 and 11312011033010.
It is not a weakly prime, because it can be changed into another prime (11312011033097) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5656005516513 + 5656005516514.
It is an arithmetic number, because the mean of its divisors is an integer number (5656005516514).
Almost surely, 211312011033027 is an apocalyptic number.
11312011033027 is a deficient number, since it is larger than the sum of its proper divisors (1).
11312011033027 is an equidigital number, since it uses as much as digits as its factorization.
11312011033027 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 756, while the sum is 25.
Adding to 11312011033027 its reverse (72033011021311), we get a palindrome (83345022054338).
The spelling of 11312011033027 in words is "eleven trillion, three hundred twelve billion, eleven million, thirty-three thousand, twenty-seven".
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