Base | Representation |
---|---|
bin | 110100101011001111… |
… | …0111111000111001111 |
3 | 101210222112110010220122 |
4 | 1221112132333013033 |
5 | 3323132222104403 |
6 | 123544444335155 |
7 | 11113136045054 |
oct | 1512636770717 |
9 | 353875403818 |
10 | 113120113103 |
11 | 43a7939a288 |
12 | 19b0b8444bb |
13 | a889a4798a |
14 | 569173502b |
15 | 2e20eb5838 |
hex | 1a567bf1cf |
113120113103 has 2 divisors, whose sum is σ = 113120113104. Its totient is φ = 113120113102.
The previous prime is 113120113079. The next prime is 113120113111. The reversal of 113120113103 is 301311021311.
It is a strong prime.
It is an emirp because it is prime and its reverse (301311021311) is a distict prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-113120113103 is a prime.
It is a Sophie Germain prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (113120115103) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 56560056551 + 56560056552.
It is an arithmetic number, because the mean of its divisors is an integer number (56560056552).
Almost surely, 2113120113103 is an apocalyptic number.
113120113103 is a deficient number, since it is larger than the sum of its proper divisors (1).
113120113103 is an equidigital number, since it uses as much as digits as its factorization.
113120113103 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 54, while the sum is 17.
Adding to 113120113103 its reverse (301311021311), we get a palindrome (414431134414).
The spelling of 113120113103 in words is "one hundred thirteen billion, one hundred twenty million, one hundred thirteen thousand, one hundred three".
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