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1131201324142 = 2565600662071
BaseRepresentation
bin10000011101100000110…
…110100110010001101110
311000010211100212021000121
4100131200312212101232
5122013200014333032
62223400002115154
7144504136415101
oct20354066462156
94003740767017
101131201324142
113a681572569a
1216329904baba
1382897009456
143ca712a8738
151e659cc7a97
hex10760da646e

1131201324142 has 4 divisors (see below), whose sum is σ = 1696801986216. Its totient is φ = 565600662070.

The previous prime is 1131201324139. The next prime is 1131201324163. The reversal of 1131201324142 is 2414231021311.

It is a semiprime because it is the product of two primes.

It is a super-2 number, since 2×11312013241422 (a number of 25 digits) contains 22 as substring.

It is a congruent number.

It is an unprimeable number.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 282800331034 + ... + 282800331037.

It is an arithmetic number, because the mean of its divisors is an integer number (424200496554).

Almost surely, 21131201324142 is an apocalyptic number.

1131201324142 is a deficient number, since it is larger than the sum of its proper divisors (565600662074).

1131201324142 is an equidigital number, since it uses as much as digits as its factorization.

1131201324142 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 565600662073.

The product of its (nonzero) digits is 1152, while the sum is 25.

Adding to 1131201324142 its reverse (2414231021311), we get a palindrome (3545432345453).

The spelling of 1131201324142 in words is "one trillion, one hundred thirty-one billion, two hundred one million, three hundred twenty-four thousand, one hundred forty-two".

Divisors: 1 2 565600662071 1131201324142