Base | Representation |
---|---|
bin | 1010010010011100100110… |
… | …1101110100101011111111 |
3 | 1111001102100001000200201101 |
4 | 2210213021231310223333 |
5 | 2440314020434414241 |
6 | 40020402024153531 |
7 | 2245160504026312 |
oct | 244471155645377 |
9 | 44042301020641 |
10 | 11312033123071 |
11 | 367145188071a |
12 | 13284210088a7 |
13 | 640949213b15 |
14 | 2b1710878979 |
15 | 1493ba47ce31 |
hex | a49c9b74aff |
11312033123071 has 2 divisors, whose sum is σ = 11312033123072. Its totient is φ = 11312033123070.
The previous prime is 11312033122991. The next prime is 11312033123077. The reversal of 11312033123071 is 17032133021311.
It is a strong prime.
It is an emirp because it is prime and its reverse (17032133021311) is a distict prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-11312033123071 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (11312033123077) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5656016561535 + 5656016561536.
It is an arithmetic number, because the mean of its divisors is an integer number (5656016561536).
Almost surely, 211312033123071 is an apocalyptic number.
11312033123071 is a deficient number, since it is larger than the sum of its proper divisors (1).
11312033123071 is an equidigital number, since it uses as much as digits as its factorization.
11312033123071 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 2268, while the sum is 28.
Adding to 11312033123071 its reverse (17032133021311), we get a palindrome (28344166144382).
The spelling of 11312033123071 in words is "eleven trillion, three hundred twelve billion, thirty-three million, one hundred twenty-three thousand, seventy-one".
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