Base | Representation |
---|---|
bin | 1010010010011100101000… |
… | …1111110110101001101101 |
3 | 1111001102100122210220221122 |
4 | 2210213022033312221231 |
5 | 2440314030230402023 |
6 | 40020402543310325 |
7 | 2245160642613014 |
oct | 244471217665155 |
9 | 44042318726848 |
10 | 11312042044013 |
11 | 36714569140a7 |
12 | 1328423bab3a5 |
13 | 64094b018499 |
14 | 2b1711b1ba7b |
15 | 1493bb1412c8 |
hex | a49ca3f6a6d |
11312042044013 has 2 divisors, whose sum is σ = 11312042044014. Its totient is φ = 11312042044012.
The previous prime is 11312042043989. The next prime is 11312042044091. The reversal of 11312042044013 is 31044024021311.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 11158893483049 + 153148560964 = 3340493^2 + 391342^2 .
It is a cyclic number.
It is not a de Polignac number, because 11312042044013 - 224 = 11312025266797 is a prime.
It is a super-2 number, since 2×113120420440132 (a number of 27 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (11312042044313) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5656021022006 + 5656021022007.
It is an arithmetic number, because the mean of its divisors is an integer number (5656021022007).
Almost surely, 211312042044013 is an apocalyptic number.
It is an amenable number.
11312042044013 is a deficient number, since it is larger than the sum of its proper divisors (1).
11312042044013 is an equidigital number, since it uses as much as digits as its factorization.
11312042044013 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 2304, while the sum is 26.
Adding to 11312042044013 its reverse (31044024021311), we get a palindrome (42356066065324).
The spelling of 11312042044013 in words is "eleven trillion, three hundred twelve billion, forty-two million, forty-four thousand, thirteen".
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