113120437 has 2 divisors, whose sum is σ = 113120438. Its totient is φ = 113120436.

The previous prime is 113120411. The next prime is 113120443. The reversal of 113120437 is 734021311.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 108284836 + 4835601 = 10406^2 + 2199^2 .

It is a cyclic number.

It is not a de Polignac number, because 113120437 - 2¹⁵ = 113087669 is a prime.

It is a Chen prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (113120407) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 56560218 + 56560219.

It is an arithmetic number, because the mean of its divisors is an integer number (56560219).

Almost surely, 2^113120437 is an apocalyptic number.

It is an amenable number.

113120437 is a deficient number, since it is larger than the sum of its proper divisors (1).

113120437 is an equidigital number, since it uses as much as digits as its factorization.

113120437 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 504, while the sum is 22.

The square root of 113120437 is about 10635.8091840725. The cubic root of 113120437 is about 483.6305108089.

Adding to 113120437 its reverse (734021311), we get a palindrome (847141748).

The spelling of 113120437 in words is "one hundred thirteen million, one hundred twenty thousand, four hundred thirty-seven".