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1131210011431 is a prime number
BaseRepresentation
bin10000011101100001010…
…111101111001100100111
311000010211222012121202001
4100131201113233030213
5122013204230331211
62223400512230131
7144504303306343
oct20354127571447
94003758177661
101131210011431
113a681a619575
1216329bb3b347
1382898a5b666
143ca724ca623
151e65a941ac1
hex107615ef327

1131210011431 has 2 divisors, whose sum is σ = 1131210011432. Its totient is φ = 1131210011430.

The previous prime is 1131210011411. The next prime is 1131210011473. The reversal of 1131210011431 is 1341100121311.

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 1131210011431 - 239 = 581454197543 is a prime.

It is a super-2 number, since 2×11312100114312 (a number of 25 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 1131210011399 and 1131210011408.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (1131210011411) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 565605005715 + 565605005716.

It is an arithmetic number, because the mean of its divisors is an integer number (565605005716).

Almost surely, 21131210011431 is an apocalyptic number.

1131210011431 is a deficient number, since it is larger than the sum of its proper divisors (1).

1131210011431 is an equidigital number, since it uses as much as digits as its factorization.

1131210011431 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 72, while the sum is 19.

Adding to 1131210011431 its reverse (1341100121311), we get a palindrome (2472310132742).

The spelling of 1131210011431 in words is "one trillion, one hundred thirty-one billion, two hundred ten million, eleven thousand, four hundred thirty-one".