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1131210030544 = 24116427329719
BaseRepresentation
bin10000011101100001010…
…111110011110111010000
311000010211222020120221221
4100131201113303313100
5122013204231434134
62223400512454424
7144504303416146
oct20354127636720
94003758216857
101131210030544
113a681a631970
1216329bb4a414
1382898a67279
143ca724d3596
151e65a9475b4
hex107615f3dd0

1131210030544 has 20 divisors (see below), whose sum is σ = 2390966655840. Its totient is φ = 514186377440.

The previous prime is 1131210030539. The next prime is 1131210030593. The reversal of 1131210030544 is 4450300121311.

It is a super-2 number, since 2×11312100305442 (a number of 25 digits) contains 22 as substring.

It is a congruent number.

It is an unprimeable number.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 3213664684 + ... + 3213665035.

It is an arithmetic number, because the mean of its divisors is an integer number (119548332792).

Almost surely, 21131210030544 is an apocalyptic number.

It is an amenable number.

1131210030544 is an abundant number, since it is smaller than the sum of its proper divisors (1259756625296).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

1131210030544 is a wasteful number, since it uses less digits than its factorization.

1131210030544 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 6427329738 (or 6427329732 counting only the distinct ones).

The product of its (nonzero) digits is 1440, while the sum is 25.

Adding to 1131210030544 its reverse (4450300121311), we get a palindrome (5581510151855).

The spelling of 1131210030544 in words is "one trillion, one hundred thirty-one billion, two hundred ten million, thirty thousand, five hundred forty-four".

Divisors: 1 2 4 8 11 16 22 44 88 176 6427329719 12854659438 25709318876 51418637752 70700626909 102837275504 141401253818 282802507636 565605015272 1131210030544