Base | Representation |
---|---|
bin | 11001101110001000001111… |
… | …000011110100010100100110 |
3 | 112211112021100001021120001200 |
4 | 121232020033003310110212 |
5 | 104311334003413113110 |
6 | 1040331041100303330 |
7 | 32553505226041344 |
oct | 3156101703642446 |
9 | 484467301246050 |
10 | 113121101301030 |
11 | 33053431694829 |
12 | 1082b763b41b46 |
13 | 4b17374203624 |
14 | 1dd113a53a994 |
15 | d1281594d6c0 |
hex | 66e20f0f4526 |
113121101301030 has 192 divisors, whose sum is σ = 312645835756800. Its totient is φ = 28323211714560.
The previous prime is 113121101300959. The next prime is 113121101301031. The reversal of 113121101301030 is 30103101121311.
113121101301030 is a `hidden beast` number, since 11 + 312 + 1 + 10 + 1 + 301 + 0 + 30 = 666.
It is a Harshad number since it is a multiple of its sum of digits (18).
It is a junction number, because it is equal to n+sod(n) for n = 113121101300994 and 113121101301012.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (113121101301031) by changing a digit.
It is a polite number, since it can be written in 95 ways as a sum of consecutive naturals, for example, 182110675 + ... + 182730785.
It is an arithmetic number, because the mean of its divisors is an integer number (1628363727900).
Almost surely, 2113121101301030 is an apocalyptic number.
113121101301030 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
It is a practical number, because each smaller number is the sum of distinct divisors of 113121101301030, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (156322917878400).
113121101301030 is an abundant number, since it is smaller than the sum of its proper divisors (199524734455770).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
113121101301030 is a wasteful number, since it uses less digits than its factorization.
113121101301030 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 622079 (or 622076 counting only the distinct ones).
The product of its (nonzero) digits is 54, while the sum is 18.
Adding to 113121101301030 its reverse (30103101121311), we get a palindrome (143224202422341).
The spelling of 113121101301030 in words is "one hundred thirteen trillion, one hundred twenty-one billion, one hundred one million, three hundred one thousand, thirty".
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