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113121101301031 is a prime number
BaseRepresentation
bin11001101110001000001111…
…000011110100010100100111
3112211112021100001021120001201
4121232020033003310110213
5104311334003413113111
61040331041100303331
732553505226041345
oct3156101703642447
9484467301246051
10113121101301031
113305343169482a
121082b763b41b47
134b17374203625
141dd113a53a995
15d1281594d6c1
hex66e20f0f4527

113121101301031 has 2 divisors, whose sum is σ = 113121101301032. Its totient is φ = 113121101301030.

The previous prime is 113121101300959. The next prime is 113121101301049. The reversal of 113121101301031 is 130103101121311.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 113121101301031 - 213 = 113121101292839 is a prime.

It is a super-2 number, since 2×1131211013010312 (a number of 29 digits) contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (113121101301731) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 56560550650515 + 56560550650516.

It is an arithmetic number, because the mean of its divisors is an integer number (56560550650516).

Almost surely, 2113121101301031 is an apocalyptic number.

113121101301031 is a deficient number, since it is larger than the sum of its proper divisors (1).

113121101301031 is an equidigital number, since it uses as much as digits as its factorization.

113121101301031 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 54, while the sum is 19.

Adding to 113121101301031 its reverse (130103101121311), we get a palindrome (243224202422342).

The spelling of 113121101301031 in words is "one hundred thirteen trillion, one hundred twenty-one billion, one hundred one million, three hundred one thousand, thirty-one".