Base | Representation |
---|---|
bin | 110100101011010001… |
… | …0110011000001010111 |
3 | 101210222121022220100102 |
4 | 1221112202303001113 |
5 | 3323133001042101 |
6 | 123544522004315 |
7 | 11113150405535 |
oct | 1512642630127 |
9 | 353877286312 |
10 | 113121112151 |
11 | 43a79a11943 |
12 | 19b1004669b |
13 | a88a007628 |
14 | 5691915155 |
15 | 2e2111186b |
hex | 1a568b3057 |
113121112151 has 2 divisors, whose sum is σ = 113121112152. Its totient is φ = 113121112150.
The previous prime is 113121112127. The next prime is 113121112163. The reversal of 113121112151 is 151211121311.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 113121112151 - 214 = 113121095767 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (113121112051) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 56560556075 + 56560556076.
It is an arithmetic number, because the mean of its divisors is an integer number (56560556076).
Almost surely, 2113121112151 is an apocalyptic number.
113121112151 is a deficient number, since it is larger than the sum of its proper divisors (1).
113121112151 is an equidigital number, since it uses as much as digits as its factorization.
113121112151 is an evil number, because the sum of its binary digits is even.
The product of its digits is 60, while the sum is 20.
Adding to 113121112151 its reverse (151211121311), we get a palindrome (264332233462).
The spelling of 113121112151 in words is "one hundred thirteen billion, one hundred twenty-one million, one hundred twelve thousand, one hundred fifty-one".
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