Base | Representation |
---|---|
bin | 11001101110001000010000… |
… | …111001011000110011010101 |
3 | 112211112021102012021101112012 |
4 | 121232020100321120303111 |
5 | 104311334034310340201 |
6 | 1040331044121034005 |
7 | 32553506052024353 |
oct | 3156102071306325 |
9 | 484467365241465 |
10 | 113121132121301 |
11 | 33053448025527 |
12 | 1082b772325905 |
13 | 4b1737a704a85 |
14 | 1dd11406807d3 |
15 | d128184da5bb |
hex | 66e210e58cd5 |
113121132121301 has 2 divisors, whose sum is σ = 113121132121302. Its totient is φ = 113121132121300.
The previous prime is 113121132121241. The next prime is 113121132121307. The reversal of 113121132121301 is 103121231121311.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 69345574105201 + 43775558016100 = 8327399^2 + 6616310^2 .
It is a cyclic number.
It is not a de Polignac number, because 113121132121301 - 238 = 112846254214357 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (113121132121307) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 56560566060650 + 56560566060651.
It is an arithmetic number, because the mean of its divisors is an integer number (56560566060651).
Almost surely, 2113121132121301 is an apocalyptic number.
It is an amenable number.
113121132121301 is a deficient number, since it is larger than the sum of its proper divisors (1).
113121132121301 is an equidigital number, since it uses as much as digits as its factorization.
113121132121301 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 216, while the sum is 23.
Adding to 113121132121301 its reverse (103121231121311), we get a palindrome (216242363242612).
The spelling of 113121132121301 in words is "one hundred thirteen trillion, one hundred twenty-one billion, one hundred thirty-two million, one hundred twenty-one thousand, three hundred one".
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