Base | Representation |
---|---|
bin | 10000011101100001011… |
… | …111110111001011110101 |
3 | 11000010212010012211101010 |
4 | 100131201133313023311 |
5 | 122013210302010201 |
6 | 2223401030022433 |
7 | 144504330360024 |
oct | 20354137671365 |
9 | 4003763184333 |
10 | 1131212141301 |
11 | 3a68208437a0 |
12 | 1632a07a7a19 |
13 | 82899325c38 |
14 | 3ca728c28bb |
15 | 1e65ac12bd6 |
hex | 107617f72f5 |
1131212141301 has 64 divisors (see below), whose sum is σ = 1679680512000. Its totient is φ = 671430133440.
The previous prime is 1131212141249. The next prime is 1131212141303. The reversal of 1131212141301 is 1031412121311.
It is a happy number.
It is not a de Polignac number, because 1131212141301 - 27 = 1131212141173 is a prime.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (1131212141303) by changing a digit.
It is a polite number, since it can be written in 63 ways as a sum of consecutive naturals, for example, 312228976 + ... + 312232598.
It is an arithmetic number, because the mean of its divisors is an integer number (26245008000).
Almost surely, 21131212141301 is an apocalyptic number.
1131212141301 is a gapful number since it is divisible by the number (11) formed by its first and last digit.
It is an amenable number.
1131212141301 is a deficient number, since it is larger than the sum of its proper divisors (548468370699).
1131212141301 is a wasteful number, since it uses less digits than its factorization.
1131212141301 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 4486.
The product of its (nonzero) digits is 144, while the sum is 21.
Adding to 1131212141301 its reverse (1031412121311), we get a palindrome (2162624262612).
The spelling of 1131212141301 in words is "one trillion, one hundred thirty-one billion, two hundred twelve million, one hundred forty-one thousand, three hundred one".
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