Base | Representation |
---|---|
bin | 1010010010011100111100… |
… | …1001101110000001101011 |
3 | 1111001102120101122001222202 |
4 | 2210213033021232001223 |
5 | 2440314212311300044 |
6 | 40020415043010415 |
7 | 2245162662144152 |
oct | 244471711560153 |
9 | 44042511561882 |
10 | 11312124321899 |
11 | 3671499300755 |
12 | 1328447669a0b |
13 | 64096209561b |
14 | 2b171ca18599 |
15 | 1493c3494c4e |
hex | a49cf26e06b |
11312124321899 has 2 divisors, whose sum is σ = 11312124321900. Its totient is φ = 11312124321898.
The previous prime is 11312124321857. The next prime is 11312124321929. The reversal of 11312124321899 is 99812342121311.
11312124321899 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-11312124321899 is a prime.
It is not a weakly prime, because it can be changed into another prime (11312124621899) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5656062160949 + 5656062160950.
It is an arithmetic number, because the mean of its divisors is an integer number (5656062160950).
Almost surely, 211312124321899 is an apocalyptic number.
11312124321899 is a deficient number, since it is larger than the sum of its proper divisors (1).
11312124321899 is an equidigital number, since it uses as much as digits as its factorization.
11312124321899 is an evil number, because the sum of its binary digits is even.
The product of its digits is 186624, while the sum is 47.
The spelling of 11312124321899 in words is "eleven trillion, three hundred twelve billion, one hundred twenty-four million, three hundred twenty-one thousand, eight hundred ninety-nine".
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