1131213000301 has 2 divisors, whose sum is σ = 1131213000302. Its totient is φ = 1131213000300.

The previous prime is 1131213000293. The next prime is 1131213000329. The reversal of 1131213000301 is 1030003121311.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 987139615401 + 144073384900 = 993549^2 + 379570^2 .

It is an emirp because it is prime and its reverse (1030003121311) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 1131213000301 - 2³ = 1131213000293 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (1131213000391) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 565606500150 + 565606500151.

It is an arithmetic number, because the mean of its divisors is an integer number (565606500151).

Almost surely, 2^{1131213000301} is an apocalyptic number.

It is an amenable number.

1131213000301 is a deficient number, since it is larger than the sum of its proper divisors (1).

1131213000301 is an equidigital number, since it uses as much as digits as its factorization.

1131213000301 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 54, while the sum is 16.

Adding to 1131213000301 its reverse (1030003121311), we get a palindrome (2161216121612).

The spelling of 1131213000301 in words is "one trillion, one hundred thirty-one billion, two hundred thirteen million, three hundred one", and thus it is an aban number.