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1131213031309 is a prime number
BaseRepresentation
bin10000011101100001100…
…011010000011110001101
311000010212011220001020101
4100131201203100132031
5122013211014000214
62223401101051101
7144504341054554
oct20354143203615
94003764801211
101131213031309
113a68212a1439
121632a0b56a91
138289957807a
143ca72a74d9b
151e65ad3b774
hex107618d078d

1131213031309 has 2 divisors, whose sum is σ = 1131213031310. Its totient is φ = 1131213031308.

The previous prime is 1131213031231. The next prime is 1131213031313. The reversal of 1131213031309 is 9031303121311.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 1100289808809 + 30923222500 = 1048947^2 + 175850^2 .

It is a cyclic number.

It is not a de Polignac number, because 1131213031309 - 213 = 1131213023117 is a prime.

It is a super-2 number, since 2×11312130313092 (a number of 25 digits) contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (1131213031349) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 565606515654 + 565606515655.

It is an arithmetic number, because the mean of its divisors is an integer number (565606515655).

Almost surely, 21131213031309 is an apocalyptic number.

It is an amenable number.

1131213031309 is a deficient number, since it is larger than the sum of its proper divisors (1).

1131213031309 is an equidigital number, since it uses as much as digits as its factorization.

1131213031309 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 1458, while the sum is 28.

The spelling of 1131213031309 in words is "one trillion, one hundred thirty-one billion, two hundred thirteen million, thirty-one thousand, three hundred nine".