Base | Representation |
---|---|
bin | 10000011101100001100… |
… | …011010000101011010101 |
3 | 11000010212011220002101111 |
4 | 100131201203100223111 |
5 | 122013211014012044 |
6 | 2223401101055021 |
7 | 144504341060164 |
oct | 20354143205325 |
9 | 4003764802344 |
10 | 1131213032149 |
11 | 3a68212a2032 |
12 | 1632a0b57471 |
13 | 82899578575 |
14 | 3ca72a753db |
15 | 1e65ad3bb34 |
hex | 107618d0ad5 |
1131213032149 has 2 divisors, whose sum is σ = 1131213032150. Its totient is φ = 1131213032148.
The previous prime is 1131213032143. The next prime is 1131213032263. The reversal of 1131213032149 is 9412303121311.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 944832600625 + 186380431524 = 972025^2 + 431718^2 .
It is a cyclic number.
It is not a de Polignac number, because 1131213032149 - 213 = 1131213023957 is a prime.
It is a self number, because there is not a number n which added to its sum of digits gives 1131213032149.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (1131213032143) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 565606516074 + 565606516075.
It is an arithmetic number, because the mean of its divisors is an integer number (565606516075).
Almost surely, 21131213032149 is an apocalyptic number.
It is an amenable number.
1131213032149 is a deficient number, since it is larger than the sum of its proper divisors (1).
1131213032149 is an equidigital number, since it uses as much as digits as its factorization.
1131213032149 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 3888, while the sum is 31.
The spelling of 1131213032149 in words is "one trillion, one hundred thirty-one billion, two hundred thirteen million, thirty-two thousand, one hundred forty-nine".
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