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11312143310 = 251387016487
BaseRepresentation
bin10101000100100000…
…11001101111001110
31002012100210102100202
422202100121233032
5141131402041220
65110254253502
7550216426436
oct124220315716
932170712322
1011312143310
114885456776
1222384b7292
1310b37b7730
147945252c6
1546319b275
hex2a2419bce

11312143310 has 16 divisors (see below), whose sum is σ = 21928154976. Its totient is φ = 4176791328.

The previous prime is 11312143307. The next prime is 11312143313. The reversal of 11312143310 is 1334121311.

It is an interprime number because it is at equal distance from previous prime (11312143307) and next prime (11312143313).

It is a super-2 number, since 2×113121433102 (a number of 21 digits) contains 22 as substring.

It is a Curzon number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (11312143313) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 43508114 + ... + 43508373.

It is an arithmetic number, because the mean of its divisors is an integer number (1370509686).

Almost surely, 211312143310 is an apocalyptic number.

11312143310 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

11312143310 is a deficient number, since it is larger than the sum of its proper divisors (10616011666).

11312143310 is a wasteful number, since it uses less digits than its factorization.

11312143310 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 87016507.

The product of its (nonzero) digits is 216, while the sum is 20.

Adding to 11312143310 its reverse (1334121311), we get a palindrome (12646264621).

The spelling of 11312143310 in words is "eleven billion, three hundred twelve million, one hundred forty-three thousand, three hundred ten".

Divisors: 1 2 5 10 13 26 65 130 87016487 174032974 435082435 870164870 1131214331 2262428662 5656071655 11312143310