Base | Representation |
---|---|
bin | 10000011101100001111… |
… | …101111000100011010111 |
3 | 11000010212200000122212201 |
4 | 100131201331320203113 |
5 | 122013214310324343 |
6 | 2223401510425331 |
7 | 144504454305301 |
oct | 20354175704327 |
9 | 4003780018781 |
10 | 1131220011223 |
11 | 3a6825229565 |
12 | 1632a3362247 |
13 | 8289ab500b3 |
14 | 3ca73970971 |
15 | 1e65b76994d |
hex | 10761f788d7 |
1131220011223 has 2 divisors, whose sum is σ = 1131220011224. Its totient is φ = 1131220011222.
The previous prime is 1131220011169. The next prime is 1131220011281. The reversal of 1131220011223 is 3221100221311.
It is a weak prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-1131220011223 is a prime.
It is a self number, because there is not a number n which added to its sum of digits gives 1131220011223.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (1131220011283) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 565610005611 + 565610005612.
It is an arithmetic number, because the mean of its divisors is an integer number (565610005612).
Almost surely, 21131220011223 is an apocalyptic number.
1131220011223 is a deficient number, since it is larger than the sum of its proper divisors (1).
1131220011223 is an equidigital number, since it uses as much as digits as its factorization.
1131220011223 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 144, while the sum is 19.
Adding to 1131220011223 its reverse (3221100221311), we get a palindrome (4352320232534).
The spelling of 1131220011223 in words is "one trillion, one hundred thirty-one billion, two hundred twenty million, eleven thousand, two hundred twenty-three".
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