Base | Representation |
---|---|
bin | 100001101101101… |
… | …0000110010011101 |
3 | 2220211120221021200 |
4 | 1003123100302131 |
5 | 4304043021000 |
6 | 304125550113 |
7 | 40014132600 |
oct | 10333206235 |
9 | 2824527250 |
10 | 1131220125 |
11 | 5305a9472 |
12 | 276a15339 |
13 | 150492129 |
14 | aa348337 |
15 | 694a1500 |
hex | 436d0c9d |
1131220125 has 72 divisors (see below), whose sum is σ = 2372261112. Its totient is φ = 517104000.
The previous prime is 1131220093. The next prime is 1131220127. The reversal of 1131220125 is 5210221311.
It can be written as a sum of positive squares in 4 ways, for example, as 21930489 + 1109289636 = 4683^2 + 33306^2 .
It is not a de Polignac number, because 1131220125 - 25 = 1131220093 is a prime.
It is a Curzon number.
It is a junction number, because it is equal to n+sod(n) for n = 1131220098 and 1131220107.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (1131220127) by changing a digit.
It is a polite number, since it can be written in 71 ways as a sum of consecutive naturals, for example, 44865 + ... + 65385.
It is an arithmetic number, because the mean of its divisors is an integer number (32948071).
Almost surely, 21131220125 is an apocalyptic number.
1131220125 is a gapful number since it is divisible by the number (15) formed by its first and last digit.
It is an amenable number.
1131220125 is an abundant number, since it is smaller than the sum of its proper divisors (1241040987).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
1131220125 is a wasteful number, since it uses less digits than its factorization.
1131220125 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 20556 (or 20536 counting only the distinct ones).
The product of its (nonzero) digits is 120, while the sum is 18.
The square root of 1131220125 is about 33633.6159964997. The cubic root of 1131220125 is about 1041.9551869229.
Adding to 1131220125 its reverse (5210221311), we get a palindrome (6341441436).
The spelling of 1131220125 in words is "one billion, one hundred thirty-one million, two hundred twenty thousand, one hundred twenty-five".
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