Base | Representation |
---|---|
bin | 10101000100100001… |
… | …00111111011001111 |
3 | 1002012100220101002002 |
4 | 22202100213323033 |
5 | 141131410421143 |
6 | 5110255422515 |
7 | 550220061035 |
oct | 124220477317 |
9 | 32170811062 |
10 | 11312201423 |
11 | 48854963a6 |
12 | 2238524a3b |
13 | 10b3808013 |
14 | 79453c555 |
15 | 4631ad5b8 |
hex | 2a2427ecf |
11312201423 has 2 divisors, whose sum is σ = 11312201424. Its totient is φ = 11312201422.
The previous prime is 11312201357. The next prime is 11312201429. The reversal of 11312201423 is 32410221311.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 11312201423 - 218 = 11311939279 is a prime.
It is a super-3 number, since 3×113122014233 (a number of 31 digits) contains 333 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 11312201395 and 11312201404.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (11312201429) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5656100711 + 5656100712.
It is an arithmetic number, because the mean of its divisors is an integer number (5656100712).
Almost surely, 211312201423 is an apocalyptic number.
11312201423 is a deficient number, since it is larger than the sum of its proper divisors (1).
11312201423 is an equidigital number, since it uses as much as digits as its factorization.
11312201423 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 288, while the sum is 20.
Adding to 11312201423 its reverse (32410221311), we get a palindrome (43722422734).
The spelling of 11312201423 in words is "eleven billion, three hundred twelve million, two hundred one thousand, four hundred twenty-three".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.098 sec. • engine limits •