Base | Representation |
---|---|
bin | 110100101011010011… |
… | …0010011001000101111 |
3 | 101210222200001112120112 |
4 | 1221112212103020233 |
5 | 3323133214431002 |
6 | 123544553410235 |
7 | 11113161251051 |
oct | 1512646231057 |
9 | 353880045515 |
10 | 113122030127 |
11 | 43a7a4895a7 |
12 | 19b1040997b |
13 | a88a269402 |
14 | 5691ab38d1 |
15 | 2e21243852 |
hex | 1a5699322f |
113122030127 has 2 divisors, whose sum is σ = 113122030128. Its totient is φ = 113122030126.
The previous prime is 113122030081. The next prime is 113122030163. The reversal of 113122030127 is 721030221311.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 113122030127 - 28 = 113122029871 is a prime.
It is a super-2 number, since 2×1131220301272 (a number of 23 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (113122050127) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 56561015063 + 56561015064.
It is an arithmetic number, because the mean of its divisors is an integer number (56561015064).
Almost surely, 2113122030127 is an apocalyptic number.
113122030127 is a deficient number, since it is larger than the sum of its proper divisors (1).
113122030127 is an equidigital number, since it uses as much as digits as its factorization.
113122030127 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 504, while the sum is 23.
Adding to 113122030127 its reverse (721030221311), we get a palindrome (834152251438).
The spelling of 113122030127 in words is "one hundred thirteen billion, one hundred twenty-two million, thirty thousand, one hundred twenty-seven".
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