Base | Representation |
---|---|
bin | 10101000100100001… |
… | …01100111110100001 |
3 | 1002012100221102110101 |
4 | 22202100230332201 |
5 | 141131412101423 |
6 | 5110300102401 |
7 | 550220205253 |
oct | 124220547641 |
9 | 32170842411 |
10 | 11312222113 |
11 | 48854aa9a5 |
12 | 2238534a01 |
13 | 10b381456a |
14 | 794545cd3 |
15 | 4631b47ad |
hex | 2a242cfa1 |
11312222113 has 2 divisors, whose sum is σ = 11312222114. Its totient is φ = 11312222112.
The previous prime is 11312222111. The next prime is 11312222143. The reversal of 11312222113 is 31122221311.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 7189683264 + 4122538849 = 84792^2 + 64207^2 .
It is a cyclic number.
It is not a de Polignac number, because 11312222113 - 21 = 11312222111 is a prime.
Together with 11312222111, it forms a pair of twin primes.
It is not a weakly prime, because it can be changed into another prime (11312222111) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5656111056 + 5656111057.
It is an arithmetic number, because the mean of its divisors is an integer number (5656111057).
Almost surely, 211312222113 is an apocalyptic number.
It is an amenable number.
11312222113 is a deficient number, since it is larger than the sum of its proper divisors (1).
11312222113 is an equidigital number, since it uses as much as digits as its factorization.
11312222113 is an odious number, because the sum of its binary digits is odd.
The product of its digits is 144, while the sum is 19.
Adding to 11312222113 its reverse (31122221311), we get a palindrome (42434443424).
The spelling of 11312222113 in words is "eleven billion, three hundred twelve million, two hundred twenty-two thousand, one hundred thirteen".
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