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113122231320000 = 263547134669323
BaseRepresentation
bin11001101110001001010010…
…011010011111110111000000
3112211112101020210121110200010
4121232021102122133313000
5104311343312204220000
61040331345144424520
732553545230042320
oct3156112232376700
9484471223543603
10113122231320000
1133053961542801
121082ba1a478140
134b174c4364ac6
141dd1206651280
15d1287ec63d50
hex66e25269fdc0

113122231320000 has 280 divisors, whose sum is σ = 427438279666816. Its totient is φ = 25856509824000.

The previous prime is 113122231319953. The next prime is 113122231320079. The reversal of 113122231320000 is 23132221311.

It is a tau number, because it is divible by the number of its divisors (280).

It is a Harshad number since it is a multiple of its sum of digits (21).

It is a congruent number.

It is an unprimeable number.

It is a polite number, since it can be written in 39 ways as a sum of consecutive naturals, for example, 66494662 + ... + 68174661.

Almost surely, 2113122231320000 is an apocalyptic number.

113122231320000 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

113122231320000 is an abundant number, since it is smaller than the sum of its proper divisors (314316048346816).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

113122231320000 is an equidigital number, since it uses as much as digits as its factorization.

113122231320000 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 134669365 (or 134669340 counting only the distinct ones).

The product of its (nonzero) digits is 432, while the sum is 21.

Adding to 113122231320000 its reverse (23132221311), we get a palindrome (113145363541311).

The spelling of 113122231320000 in words is "one hundred thirteen trillion, one hundred twenty-two billion, two hundred thirty-one million, three hundred twenty thousand".