Base | Representation |
---|---|
bin | 11001101110001001010010… |
… | …011010011111110111000000 |
3 | 112211112101020210121110200010 |
4 | 121232021102122133313000 |
5 | 104311343312204220000 |
6 | 1040331345144424520 |
7 | 32553545230042320 |
oct | 3156112232376700 |
9 | 484471223543603 |
10 | 113122231320000 |
11 | 33053961542801 |
12 | 1082ba1a478140 |
13 | 4b174c4364ac6 |
14 | 1dd1206651280 |
15 | d1287ec63d50 |
hex | 66e25269fdc0 |
113122231320000 has 280 divisors, whose sum is σ = 427438279666816. Its totient is φ = 25856509824000.
The previous prime is 113122231319953. The next prime is 113122231320079. The reversal of 113122231320000 is 23132221311.
It is a tau number, because it is divible by the number of its divisors (280).
It is a Harshad number since it is a multiple of its sum of digits (21).
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 39 ways as a sum of consecutive naturals, for example, 66494662 + ... + 68174661.
Almost surely, 2113122231320000 is an apocalyptic number.
113122231320000 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
It is an amenable number.
113122231320000 is an abundant number, since it is smaller than the sum of its proper divisors (314316048346816).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
113122231320000 is an equidigital number, since it uses as much as digits as its factorization.
113122231320000 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 134669365 (or 134669340 counting only the distinct ones).
The product of its (nonzero) digits is 432, while the sum is 21.
Adding to 113122231320000 its reverse (23132221311), we get a palindrome (113145363541311).
The spelling of 113122231320000 in words is "one hundred thirteen trillion, one hundred twenty-two billion, two hundred thirty-one million, three hundred twenty thousand".
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