Base | Representation |
---|---|
bin | 10101000100100001… |
… | …01111101010001111 |
3 | 1002012100221222112102 |
4 | 22202100233222033 |
5 | 141131412424403 |
6 | 5110300225315 |
7 | 550220252303 |
oct | 124220575217 |
9 | 32170858472 |
10 | 11312233103 |
11 | 4885508186 |
12 | 223853b23b |
13 | 10b3819572 |
14 | 794549d03 |
15 | 4631b7b88 |
hex | 2a242fa8f |
11312233103 has 2 divisors, whose sum is σ = 11312233104. Its totient is φ = 11312233102.
The previous prime is 11312233099. The next prime is 11312233111. The reversal of 11312233103 is 30133221311.
11312233103 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 11312233103 - 22 = 11312233099 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (11312233123) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5656116551 + 5656116552.
It is an arithmetic number, because the mean of its divisors is an integer number (5656116552).
Almost surely, 211312233103 is an apocalyptic number.
11312233103 is a deficient number, since it is larger than the sum of its proper divisors (1).
11312233103 is an equidigital number, since it uses as much as digits as its factorization.
11312233103 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 324, while the sum is 20.
Adding to 11312233103 its reverse (30133221311), we get a palindrome (41445454414).
The spelling of 11312233103 in words is "eleven billion, three hundred twelve million, two hundred thirty-three thousand, one hundred three".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.069 sec. • engine limits •