Base | Representation |
---|---|
bin | 10101000100100010… |
… | …00000110000001101 |
3 | 1002012101002112120112 |
4 | 22202101000300031 |
5 | 141131422144432 |
6 | 5110301525405 |
7 | 550220663363 |
oct | 124221006015 |
9 | 32171075515 |
10 | 11312303117 |
11 | 4885555845 |
12 | 2238573865 |
13 | 10b38423ab |
14 | 794567633 |
15 | 4631cd7b2 |
hex | 2a2440c0d |
11312303117 has 2 divisors, whose sum is σ = 11312303118. Its totient is φ = 11312303116.
The previous prime is 11312303069. The next prime is 11312303137. The reversal of 11312303117 is 71130321311.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 6125566756 + 5186736361 = 78266^2 + 72019^2 .
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-11312303117 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 11312303092 and 11312303101.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (11312303137) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (11) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5656151558 + 5656151559.
It is an arithmetic number, because the mean of its divisors is an integer number (5656151559).
Almost surely, 211312303117 is an apocalyptic number.
It is an amenable number.
11312303117 is a deficient number, since it is larger than the sum of its proper divisors (1).
11312303117 is an equidigital number, since it uses as much as digits as its factorization.
11312303117 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 378, while the sum is 23.
Adding to 11312303117 its reverse (71130321311), we get a palindrome (82442624428).
The spelling of 11312303117 in words is "eleven billion, three hundred twelve million, three hundred three thousand, one hundred seventeen".
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