Base | Representation |
---|---|
bin | 110100101011010101… |
… | …0011000101001000001 |
3 | 101210222202001221212201 |
4 | 1221112222120221001 |
5 | 3323134003214444 |
6 | 123545032353201 |
7 | 11113203331624 |
oct | 1512652305101 |
9 | 353882057781 |
10 | 113123101249 |
11 | 43a80050324 |
12 | 19b10845801 |
13 | a88a552b02 |
14 | 5691cb1dbb |
15 | 2e213a5dd4 |
hex | 1a56a98a41 |
113123101249 has 2 divisors, whose sum is σ = 113123101250. Its totient is φ = 113123101248.
The previous prime is 113123101229. The next prime is 113123101277. The reversal of 113123101249 is 942101321311.
It is an a-pointer prime, because the next prime (113123101277) can be obtained adding 113123101249 to its sum of digits (28).
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 101872680625 + 11250420624 = 319175^2 + 106068^2 .
It is a cyclic number.
It is not a de Polignac number, because 113123101249 - 233 = 104533166657 is a prime.
It is a super-3 number, since 3×1131231012493 (a number of 34 digits) contains 333 as substring.
It is not a weakly prime, because it can be changed into another prime (113123101229) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 56561550624 + 56561550625.
It is an arithmetic number, because the mean of its divisors is an integer number (56561550625).
Almost surely, 2113123101249 is an apocalyptic number.
It is an amenable number.
113123101249 is a deficient number, since it is larger than the sum of its proper divisors (1).
113123101249 is an equidigital number, since it uses as much as digits as its factorization.
113123101249 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 1296, while the sum is 28.
The spelling of 113123101249 in words is "one hundred thirteen billion, one hundred twenty-three million, one hundred one thousand, two hundred forty-nine".
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