Base | Representation |
---|---|
bin | 10000011101100010101… |
… | …011100111100001100111 |
3 | 11000010220111120202112022 |
4 | 100131202223213201213 |
5 | 122013230343000403 |
6 | 2223403015413355 |
7 | 144504661230302 |
oct | 20354253474147 |
9 | 4003814522468 |
10 | 1131232000103 |
11 | 3a6830a77a27 |
12 | 1632a738425b |
13 | 828a0489cca |
14 | 3ca753b1b39 |
15 | 1e65c836d38 |
hex | 10762ae7867 |
1131232000103 has 2 divisors, whose sum is σ = 1131232000104. Its totient is φ = 1131232000102.
The previous prime is 1131232000051. The next prime is 1131232000141. The reversal of 1131232000103 is 3010002321311.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 1131232000103 - 214 = 1131231983719 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (1131232000303) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 565616000051 + 565616000052.
It is an arithmetic number, because the mean of its divisors is an integer number (565616000052).
Almost surely, 21131232000103 is an apocalyptic number.
1131232000103 is a deficient number, since it is larger than the sum of its proper divisors (1).
1131232000103 is an equidigital number, since it uses as much as digits as its factorization.
1131232000103 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 108, while the sum is 17.
Adding to 1131232000103 its reverse (3010002321311), we get a palindrome (4141234321414).
The spelling of 1131232000103 in words is "one trillion, one hundred thirty-one billion, two hundred thirty-two million, one hundred three", and thus it is an aban number.
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