Base | Representation |
---|---|
bin | 1010010010011101101110… |
… | …1010000111001011000011 |
3 | 1111001110010000102221110012 |
4 | 2210213123222013023003 |
5 | 2440320130014440344 |
6 | 40020451540055135 |
7 | 2245201120443056 |
oct | 244473352071303 |
9 | 44043100387405 |
10 | 11312334140099 |
11 | 367159678a223 |
12 | 13284a59944ab |
13 | 6409966a97c5 |
14 | 2b173c834a9d |
15 | 1493d6add29e |
hex | a49dba872c3 |
11312334140099 has 2 divisors, whose sum is σ = 11312334140100. Its totient is φ = 11312334140098.
The previous prime is 11312334140047. The next prime is 11312334140117. The reversal of 11312334140099 is 99004143321311.
11312334140099 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 11312334140099 - 220 = 11312333091523 is a prime.
It is not a weakly prime, because it can be changed into another prime (11312334170099) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5656167070049 + 5656167070050.
It is an arithmetic number, because the mean of its divisors is an integer number (5656167070050).
Almost surely, 211312334140099 is an apocalyptic number.
11312334140099 is a deficient number, since it is larger than the sum of its proper divisors (1).
11312334140099 is an equidigital number, since it uses as much as digits as its factorization.
11312334140099 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 69984, while the sum is 41.
The spelling of 11312334140099 in words is "eleven trillion, three hundred twelve billion, three hundred thirty-four million, one hundred forty thousand, ninety-nine".
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