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11312334140099 is a prime number
BaseRepresentation
bin1010010010011101101110…
…1010000111001011000011
31111001110010000102221110012
42210213123222013023003
52440320130014440344
640020451540055135
72245201120443056
oct244473352071303
944043100387405
1011312334140099
11367159678a223
1213284a59944ab
136409966a97c5
142b173c834a9d
151493d6add29e
hexa49dba872c3

11312334140099 has 2 divisors, whose sum is σ = 11312334140100. Its totient is φ = 11312334140098.

The previous prime is 11312334140047. The next prime is 11312334140117. The reversal of 11312334140099 is 99004143321311.

11312334140099 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 11312334140099 - 220 = 11312333091523 is a prime.

It is not a weakly prime, because it can be changed into another prime (11312334170099) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5656167070049 + 5656167070050.

It is an arithmetic number, because the mean of its divisors is an integer number (5656167070050).

Almost surely, 211312334140099 is an apocalyptic number.

11312334140099 is a deficient number, since it is larger than the sum of its proper divisors (1).

11312334140099 is an equidigital number, since it uses as much as digits as its factorization.

11312334140099 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 69984, while the sum is 41.

The spelling of 11312334140099 in words is "eleven trillion, three hundred twelve billion, three hundred thirty-four million, one hundred forty thousand, ninety-nine".