11312334140117 has 2 divisors, whose sum is σ = 11312334140118. Its totient is φ = 11312334140116.

The previous prime is 11312334140099. The next prime is 11312334140141. The reversal of 11312334140117 is 71104143321311.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 8368343910481 + 2943990229636 = 2892809^2 + 1715806^2 .

It is a cyclic number.

It is not a de Polignac number, because 11312334140117 - 2¹⁴ = 11312334123733 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (11312334140417) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5656167070058 + 5656167070059.

It is an arithmetic number, because the mean of its divisors is an integer number (5656167070059).

Almost surely, 2^{11312334140117} is an apocalyptic number.

It is an amenable number.

11312334140117 is a deficient number, since it is larger than the sum of its proper divisors (1).

11312334140117 is an equidigital number, since it uses as much as digits as its factorization.

11312334140117 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 6048, while the sum is 32.

Adding to 11312334140117 its reverse (71104143321311), we get a palindrome (82416477461428).

The spelling of 11312334140117 in words is "eleven trillion, three hundred twelve billion, three hundred thirty-four million, one hundred forty thousand, one hundred seventeen".