Base | Representation |
---|---|
bin | 1010010010011101101110… |
… | …1010000111001011010010 |
3 | 1111001110010000102221110202 |
4 | 2210213123222013023102 |
5 | 2440320130014440424 |
6 | 40020451540055202 |
7 | 2245201120443110 |
oct | 244473352071322 |
9 | 44043100387422 |
10 | 11312334140114 |
11 | 367159678a237 |
12 | 13284a5994502 |
13 | 6409966a9807 |
14 | 2b173c834ab0 |
15 | 1493d6add2ae |
hex | a49dba872d2 |
11312334140114 has 16 divisors (see below), whose sum is σ = 19392818247168. Its totient is φ = 4848081844032.
The previous prime is 11312334140099. The next prime is 11312334140117. The reversal of 11312334140114 is 41104143321311.
11312334140114 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a Curzon number.
It is not an unprimeable number, because it can be changed into a prime (11312334140117) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 3958562 + ... + 6188285.
It is an arithmetic number, because the mean of its divisors is an integer number (1212051140448).
Almost surely, 211312334140114 is an apocalyptic number.
11312334140114 is a gapful number since it is divisible by the number (14) formed by its first and last digit.
11312334140114 is a deficient number, since it is larger than the sum of its proper divisors (8080484107054).
11312334140114 is a wasteful number, since it uses less digits than its factorization.
11312334140114 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 10226489.
The product of its (nonzero) digits is 3456, while the sum is 29.
Adding to 11312334140114 its reverse (41104143321311), we get a palindrome (52416477461425).
The spelling of 11312334140114 in words is "eleven trillion, three hundred twelve billion, three hundred thirty-four million, one hundred forty thousand, one hundred fourteen".
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