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1131242301422 = 2565621150711
BaseRepresentation
bin10000011101100011010…
…010111010011111101110
311000010221012222010021122
4100131203102322133232
5122013241012121142
62223404024300542
7144505144623302
oct20354322723756
94003835863248
101131242301422
113a6836873512
121632aa911752
13828a2655a6c
143ca768d3d02
151e65d6be1d2
hex107634ba7ee

1131242301422 has 4 divisors (see below), whose sum is σ = 1696863452136. Its totient is φ = 565621150710.

The previous prime is 1131242301353. The next prime is 1131242301463. The reversal of 1131242301422 is 2241032421311.

It is a happy number.

It is a semiprime because it is the product of two primes.

It is a junction number, because it is equal to n+sod(n) for n = 1131242301391 and 1131242301400.

It is a congruent number.

It is an unprimeable number.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 282810575354 + ... + 282810575357.

It is an arithmetic number, because the mean of its divisors is an integer number (424215863034).

Almost surely, 21131242301422 is an apocalyptic number.

1131242301422 is a deficient number, since it is larger than the sum of its proper divisors (565621150714).

1131242301422 is an equidigital number, since it uses as much as digits as its factorization.

1131242301422 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 565621150713.

The product of its (nonzero) digits is 2304, while the sum is 26.

Adding to 1131242301422 its reverse (2241032421311), we get a palindrome (3372274722733).

The spelling of 1131242301422 in words is "one trillion, one hundred thirty-one billion, two hundred forty-two million, three hundred one thousand, four hundred twenty-two".

Divisors: 1 2 565621150711 1131242301422