113126613137 has 2 divisors, whose sum is σ = 113126613138. Its totient is φ = 113126613136.

The previous prime is 113126613121. The next prime is 113126613139. The reversal of 113126613137 is 731316621311.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 94686059521 + 18440553616 = 307711^2 + 135796^2 .

It is a cyclic number.

It is not a de Polignac number, because 113126613137 - 2⁴ = 113126613121 is a prime.

Together with 113126613139, it forms a pair of twin primes.

It is a Chen prime.

It is a junction number, because it is equal to n+sod(n) for n = 113126613097 and 113126613106.

It is not a weakly prime, because it can be changed into another prime (113126613139) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 56563306568 + 56563306569.

It is an arithmetic number, because the mean of its divisors is an integer number (56563306569).

Almost surely, 2^113126613137 is an apocalyptic number.

It is an amenable number.

113126613137 is a deficient number, since it is larger than the sum of its proper divisors (1).

113126613137 is an equidigital number, since it uses as much as digits as its factorization.

113126613137 is an evil number, because the sum of its binary digits is even.

The product of its digits is 13608, while the sum is 35.

The spelling of 113126613137 in words is "one hundred thirteen billion, one hundred twenty-six million, six hundred thirteen thousand, one hundred thirty-seven".